if the 17th term of an A.P exceeds its 10th term by 7.find the common difference
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Answered by
6
an=a+(n-1)d
17th term=a+16d
10th term=a+9d
(a+16d)-(a+9d)=7
a+16d-a-9d=7
7d=7
d=1
Answered by
3
Answer:
a17=a10+7
a+16d=a+9d+7
a and a are getting cancelled
16d-9d=7
7d=7
d=1
therefore the common difference is 1
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