Question

if the 17th term of an a.p is 1/9 and its ninth term is 1/7.find it's 63rd term​

Answer 1

Answer:

Step-by-step explanation:

Solution :-

Let the first term be a and the common difference be d of the given A.P.

Given, a(7) = 1/9

⇒ a + 6d = 1/9 ..... (i)

⇒ a(9) = 1/7

⇒ a + 8d = 1/7 .... (ii)

On subtracting eq (i) from (ii), we get

⇒ a + 8d - a - 6d = 1/7 - 1/9

⇒ 2d = 2/63

⇒ d = 1/63

Substituting the value of d in Eq (ii), we get

⇒ a + 8 × 1/63 = 1/7

⇒ a = 1/7 - 8/63

⇒ a = 9 - 8/63

⇒ a = 1/63

Now, a(63) = 1/63 + 62 × 1/63

⇒ a(63 = 1 + 62/63

⇒ a(63) = 63/63

⇒ a(63) = 1

Hence, the 63rd term of an A.P. is 1.

Answer 2

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