if the 17th term of an AP exceeds the 10th term by 7 find the AP?
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Answered by
16
Answer:
a17 = a10 +7
a + 16d = a + 9d +7
a +16d -(a+9d) = 7
a +16d -a - 9d = 7
7d = 7
Therefore d = 1
Step-by-step explanation:
H4MDAN:
The question cannot be " Find the Ap" it is most likely . "Find the common Diffrence"
Answered by
9
☺ Hello mate__ ❤
◾◾here is your answer...
Given, 17th term exceeds its 10th term by 7.
It means a17 = a10 + 7 ........eq(1)
Here, a17 is the 17th term and a10 is the 10th term of an AP.
Using formula an=a+(n−1)d, to find nth term of arithmetic progression, we get
a17=a+(16)d ..........eq (2)
a10=a+(9)d .........eq(3)
Putting (2) and (3) in equation (1), we get
a+16d=a+9d+7
⇒7d=7
⇒d=7/7=1
I hope, this will help you.
Thank you______❤
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