Question

If the 17th term of an AP exceeds
the 13th term of the AP by to then
find common difference.​

Answer 1

Answer:

given:-

17th term - 13th term = 2

so, 17th term= a+16d

13th term=a+12d

solution:-

a+16d-(a+12d)=2

a+16d-a-12d=2

4d=2

$d = \frac{1}{2}$

hope it helps you....✌✌

Answer 2

Answer:

refer to the attachment for ur answer

hope it helps you