Question

if the 19th term of an AP exceeds the 12th term of AP by 7 upon 4 then the common difference is​

Answer 1

Answer:

$d=\frac{1}{4}$

Step-by-step explanation:

Given:-

a₁₉-a₁₂=7/4

To Find:-

Common Difference(d).

Formula that You have to always remember:-

aₙ=a+(n-1)d

Solution:-

a₁₉-a₁₂=7/4

(a+18d)-(a+11d)=7/4

a-a+18d-11d=7/4

7d=7/4

$d=\frac{7}{4} * \frac{1}{7}$

$d=\frac{1}{4}$