if the 2 diagonals of a rhombus are 90 m and 400m then find the height and perimeter ?
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Answer:
side of the Rhombus=v45^2+200^2
=v2025 +40000=v42025
=205m
Area of Rhombus=dixd2/2
90x400/2=18000m2
bxh=18000
205xh=18000
h = 18000/205=87.8m
Perimeter=4 x 205 =820m
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