If the 2 digit no. are interchanged, the no. so obtained is greater than the original no. by 18. If the sum of the two digits of the number is 14. What is the original no. ?
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Answered by
1
original number is 68
HenryMangKuki:
Explain pls,.
let number is 10x + y than interchaneged number is 10y + x. ..bcz given that interchanged number is greater by 18 so,. 10y+x -10x-y = 18 ...by this equation we got y-x =2 ......now in question given that sum of digit x+y = 14 ...now both equation y= 8 and x = 6.....bcz original number is 10x+y so number is 10*6+8=68......gotted
Answered by
5
Let the two digits be x and y
The number is 10x + y
The number when digits are interchanged = 10y + x
According to the given condition,
10y + x - 18 = 10x + y
10y - y -18 = 10x -x
9y - 18 = 9x
x = (9y - 18)/9
x = y - 2
According to the given condition,
x + y = 14
Putting x = y - 2 in x + y = 14
Therefore y - 2+ y = 14
2y = 14 + 2
y = 16/2
y = 8
Therefore put y = 8 in x + y = 14
x + 8 = 14
x = 14 - 8
x = 6
So the number is 10 x + y
= 10 * 6 + 8
= 60 + 8
= 68
Hope this helps you . Please make this a brainlist answer.
The number is 10x + y
The number when digits are interchanged = 10y + x
According to the given condition,
10y + x - 18 = 10x + y
10y - y -18 = 10x -x
9y - 18 = 9x
x = (9y - 18)/9
x = y - 2
According to the given condition,
x + y = 14
Putting x = y - 2 in x + y = 14
Therefore y - 2+ y = 14
2y = 14 + 2
y = 16/2
y = 8
Therefore put y = 8 in x + y = 14
x + 8 = 14
x = 14 - 8
x = 6
So the number is 10 x + y
= 10 * 6 + 8
= 60 + 8
= 68
Hope this helps you . Please make this a brainlist answer.
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