If the 2 zeroes of the polynomial x 4- 6x 3- 26x 2+138x -35 are 2±√3, find the others.
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f(x)=(x2-2)={x2-(√2)2}=(x+√2)(x-√2). ⇒x=-√2orx=√2. So, the zeros of f(x) are -√2and√2.
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