Question

If the 22nd term exceeds the 18th term by 12, find d?

Answer 1

Answer:

tn=a+(n-1)d

Hence,

t21=a+20d

t18=a+17d

According to the given condition.

t21-t18=12

(a+20d)-(a+17d)=12

3d=12

d=12/3

d=4

Hence common difference is 4.

Answer 2

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