if the 23 term is 35 more than its 16 term find D ( ch aerthmatic progression class 10 )
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Taxi fare for first 2 km = 15 + 8 = 23 ... First four terms of this A.P. will be 10, 20, 30, and 40. ... If they form an A.P. find the common difference d and write three more terms. ... 35 = 7 + 12 d.
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Let a and d be the first term and common difference of AP respectively.
23 term is 35 more than the 16th term
t23 = t16+35
a+(23–1)d= a+(16–1)d+35
22d=15d+35
7d=35
d=5
Step-by-step explanation:
hope it helps you.
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