If the 26th term of an ap is 10.Find the sum of the first 51 terms of the ap
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Answer:
Step-by-step explanation:
a26= 10
s51=?
We know that an= a+(n-1)d
So, a26= a+ 25d
=> 10= a+25d
=> a= 10-25d -------1
Now, sn= n/2(2a +(n-1)d)
So s51= 51/2 (2(10-25d) + 50d)
=> s51 = 51/2 (20-50d+50d)
=> s51= 51/2 (20)
s51= 510
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