If the 2nd term of an AP is 13 and the 5th term is 25,what is its 7th term? (a) 30,(b) 33,(c) 37,(d) 38
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a+d = 13
a+4d = 25
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-3d = -12
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d = 4,substitute in a+d= 13
a+4 = 13
a = 13-4
a= 9
7th term = a+6d = 9+6(4) = 33
answer is b...
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