If the 2nd term to 12 and the 4th term in 24 find a and d?
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Answer:
a = 6, d = 6
Step-by-step explanation:
let a be the first term and d be the common difference
t₂ = a + d = 12 ----- (i)
t₄ = a + 3d = 24 ----- (ii)
subtract (i) from (ii)
a + 3d = 24
a + d = 12
- - -
--------------------
2d = 12
=> d = 6
substitute value of d in (i)
a + d = 12
a + 6= 12
=> a = 6.
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