if the 3 and 6 term of AP is 7 and 13 then find a and d
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a3=a+(3-1) d=a+2d=7_____1
a6=a+(6-1) d=a+5d=13______2
solving 1 and 2
a+2d=7
a+5d=13
______
-3d=-6
d=6/3
d=2
putting value of d in 1
a+2*2=7
a+4=7
a=7-4
a=3.
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Answer:
"a" is 3. and. "d" is 2.
Step-by-step explanation:
while doing such question, write the given terms in general form a+(n-1)d. then equate those equations.... we will get d. substitute d in any of the equation
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