if the 3 consecutive term of an AP are x+4, 2x+x and 12, find the value of x
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0
Answer:
The three consecutive terms are ( x+4),(2x+x) & 12
So, their common difference should be equal
so, (2x+x)-(x+4)=12-(2x+x)
Now you can find the value of x!!!
Answered by
0
Answer:
we know that (2x+x)-(x+4)=d
2x-4 =d (1)
also 12-(2x+x)=d
12-3x=d (2)
from (1) and (2) we get
2x-4=12-3x
5x=16
x=16/5
Step-by-step explanation:
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