Question

if the 39th and 51st terms of an Ap are 51 and 39 respectively then which term of this Ap is zero?​

Answer 1

Step-by-step explanation:

a+38d=51

a+50d=39

by subtracting both the equations

we get

12d=- -12

d=-1

a+38(-1)=51

a=89

let the nth term be 0

a+(n-1)d=0

89+(n-1)-1=0

1-n=-89

-n=-90

n=90

Therefore 90th term is 0

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