Math, asked by sharansai42, 9 months ago

If the 39th and 51st terms of an AP are 59 and 31 Respectively..
Then which term of this AP is equal to 0​

Answers

Answered by anushka603
0

Answer:

a+38d=59............(i)

a+50d=31.............(ii)

solving both the equation find the value of a and d.....

then put the value of a and d in the equation given below

a+(n-1)d=0

thus u will get the value of n i.e the term of AP having value 0

please mark it as brainliest

Answered by Anonymous
3

Step-by-step explanation:

↙️↘️◆↙️↘️◆↙️↘️◆↙️↘️◆↙️↙️◆↘️↙️

\huge{\underline{\mathscr{\purple{Hey,mate..!}}}}

\huge{\red{\mathfrak{Answer}}}

<a><b><i><body bgcolor="yellow">  

❤️_________✍️_________❤️

✳️❇️✳️❇️✳️❇️✳️❇️✳️

a+38d=59

a+50d=31

cevescsccenes

ceeee

then put the value of a and d in the equation given below

a+(n-1)d=0

thus u will get the value of n i.e the term of AP having

value O

【◆】●【◆】●【◆】●【◆】●【◆】●【◆】

&lt;marquee r]</p><p>‌[tex]\large{\red{\boxed{\mathbb{Hope\: It\: Helps}}}}

❤️

✨✨

✳️✳️✳️

✔️✔️✔️✔️

➖➖➖➖➖

follow me

❤️silentmunda ❤️

Similar questions