Question

if the 3angles of a triangle are in the ratio 3:5:4,then find them​

Answer 1

Answer:

$let \\ 3x + 5x + 4x = 180 \\ 12x = 180 \\ x = 180 \div 12 = 15 \\ the \:\:side \: length \: of \: triangle = 3 x = 3 \times 15 = 45 \\ 4x = 4 \times 15=60 \\ 5x = 5 \times 15=75$

hope this answer is helpful for you

Answer 2

Answer:

$\huge\bigstar\underbrace{\mathtt\red{A} \mathtt\purple{N} \mathtt\green{S}\mathtt\blue{W} \mathtt\blue{E} \mathtt\orange{R}}\bigstar$

Step-by-step explanation:

$\huge{\textsf{\red{\underline{Question:}}}}$

if the three angles of a triangle are in the ratio 3:5:4, then find them.....

$\huge{\textsf{\orange{\boxed{Assumption:}}}}$

Let the ratios be:

➪3x=A

➪5x=B

➪4x=C respectively.......

$\huge{\textsf{\blue{\boxed{Theorm:}}}}$

The sum of interior angles of a triangle are 180°[Angle Sum Property]

$\huge{\textsf{\purple{\boxed{Solution:}}}}$

$\angle{A}$+$\angle{B}$+$\angle{C}$= 180°

3x+5x+4x=180°

12x= 180°

x= $\large\frac{180}{12}$

x= 15°

$\huge{\textsf{\green{\underline{Substitution:}}}}$

$\angle{A}$= 3x= 3$\times$15= 45°

$\angle{B}$= 5x= 5$\times$15= 75°

$\angle{C}$= 4x= 4$\times$15 = 60°