If the 3rD
7th and 12th terms of an AP are three consecutive terms of a GP find the common ratio of GP
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Step-by-step explanation:
3rd term of AP-- a+2d
7th term of AP-- a+6d
12th term of AP-- a+11d
The above terms are in GP
(a+2d)(a+11d)=(a+6d)^2
a^2+13ad+22d^2=a^2+12ad+36d^2
ad=14d^2
a=14d
Common ratio=(a+2d)/(a+6d)
=16d/20d
=4/5
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