Question

If the 3rd and 6th term of an ap are 7 and 13 respectively find its 10th term

Answer 1

Given:a3=7,a6=13
To find:a10
Solution:
By elimination method,
a3=+a+2d=+7
a6=+a+5d=+13
- - -
-3d=-6
d=2
a3=a+2(2)=7
a=3

a=3,d=2
So, Tenth term,a10=a+9d
=3+9(2)=21

Answer 2

The 10th term of an A.P. is 21.

Step-by-step explanation:

Given : If the 3rd and 6th term of an A.P are 7 and 13 respectively.

To find : Its 10th term ?

Solution :

The third term of an A.P is $a_3=a+2d$

i.e. $a+2d=7$ ....(1)

The sixth term of an A.P is $a_6=a+5d$

i.e. $a+5d=13$  ....(2)

Subtract (1) and (2),

$a+5d-(a+2d)=13-7$

$3d=6$

$d=\frac{6}{3}$

$d=2$

Substitute in (1),

$a+2(2)=7$

$a=7-4$

$a=3$

The 10th term of an A.P is $a_{10}=a+9d$

$a_{10}=3+9(2)$

$a_{10}=3+18$

$a_{10}=21$

Therefore, the 10th term of an A.P. is 21.

#Learn more

Write the common difference of an A.P. whose nth term is an= 3n + 7.

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