Question

if the 3rd and the 9 th term of an AP are 4 and -8 respectively which term of this AP is zero​

Answer 1

Step-by-step explanation:

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Answer 2

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To Solve:

• Which Term of the A.P will be 0

Given:

• 3rd term = 4
• 9th term = -8

Solⁿ:

• Make Eqⁿ
• Solve by Elimination Method
• Find value of d and a
• Find the n term

3rd term = 4

Eqⁿ:

a + 2d = 4 -----------(1)

9th term = -8

Eqⁿ:

a + 8d = -8 -----------(2)

Solving through Elimination:

ㅤaㅤ+ㅤ2dㅤ=ㅤ4

± aㅤ±ㅤ8dㅤ= ±8

=> -6d = 12

= d = 12/-6

= d = –2

Value of A:

a + 2d = 4

a + 2(-2) = 4

a -4 = 4

a = 4+4

a = 8

The Term which is 0 :-

aⁿ = 0, n = ?, d = –2, a = 8

=> aⁿ = a + ( n-1 ) d

=> 0 = 8 + ( n-1 ) (–2)

=> 0 = 8 –2n + 2

=> 0 = 10 – 2n

=> –10 = -2n

=> 10 = 2n

=> 5 = n

★ 5th Term is 0.

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