If the 3rd and the 9th of an AP are 4 and minus 8 respectively, which term of this AP is zero?
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Answer:
Step-by-step explanation:
T3=4
T9=-8
T3=a+2d=4
T9=a+8d=-8
By eliminating this we get
-6d=12 ok
d=-2
a+2d=4
a-4=4
a=8.
By general formula Tn=a+(n-1)d
Take Tn=0
0=8+(n-1)-2
0=8-2n+2
2n=10
n=5.
The fifth term of a.p is zero
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