If the 3rd and the 9th terms of an AP are 4 and – 8 respectively, which term of this AP is zero?
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a+2d=4 eq1
a+8d=-8
a+8d=-8
a=-8-8d
a=8(1-d)
putting a in eq 1
8-8d+2d=4
4=6d
d=2/3
putting in EQ1
a=4-4/3
8/3
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