if the 3rd and the 9th terms of an ap are 4 and-8 recpetively find the 25th terms
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Answer:
refer the attachment.
hope it helps..
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Answered by
0
Answer:
-40
Step-by-step explanation:
t3 = 4
a+(3-1)d =4
a+2d=4 __ (1)
t9=8
a+(9-1)d =8
a+8d=8 __ (2)
from 1 and 2 ,
a+2d=4
a+8d=8
6d =-12
d =-2
putting the value d in eq 1 we get ,
a+2d=4
a+2x(-2)=4
a-4 =4
a= 8
now , T25 =a+(n-1)d
=8+(25-1)(-2)
=8+ 24(-2)
=8-48
=-40
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