If the 3rd term and 9th term of an ap are 4 and minus minus 8 respectively which term of the ap is zero
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Answer:
given
T3=4=a+2d.....eq(1)
T9=-8=a+8d.....eq(2)
subrtact eq(1)by eq(2),we get
12=-6d
d=-2 put the value of d in eq(1),we get
a=8,now expand the AP with comman difference -2
8,6,4,2,0,-2,-4,-6,-8,.....hence 5th term of the A.P. is zero
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Please refer the attachment dear
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