If the 3rd term and the 9th term of an AP are 4 and -8 respectively, which term of this AP is zero
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5
Answer:
Zero is the 5th term of the AP
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Answer:
5th term of the A.P is zero .
Step-by-step explanation:
Given , the third term of the AP is 4 and ninth term of the AP is -8
nth term of a series in AP is
Tn = a+(n-1)d
where
a is first term and
d is the common difference .
so , third term of AP :
T3 = a+(3-1)d=4
a + 2d = 4 ........... eq (1)
and ninth term of AP :
T4 = a+(9-1)d= -8
a + 8d = -8 .......... eq(2)
eq(2)-eq(1) :
(a+8d) - ( a + 2d ) = -8-4
6d=-12
d=-2
substitute the value of d in equation (1) , we get the value of "a"
a+2d=4
a+2(-2)=4
a=8
let an nth term in the AP be equal to zero , substitute values of "a" and "d"
a+(n-1)d=0
8+(n-1)(-2)=0
-2n+2=-8
-2n=-10
n=5
therefore 5th term of the AP is zero
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