if the 3rd term of an ap is 12 and 50th term is 106 , then find it's 29th term
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Answer:
29th term = 64.
Step-by-step explanation:
Given
a3 = 12
a50 = 106
Solution
an = a + (n - 1)d
a3 = a + (3 - 1)d
12 = a + 2d
a + 2d = 12____(1)
a50 = a + (50-1)d
106 = a + (49)d
a + 49d = 106_____(2)
Solving equation 1 and 2
a + 2d = 12
a + 49d = 106
-47d = -94
d = -94/-47
d = 2
Putting value of d in eq 1
a + 2d = 12
a + 2×2 = 12
a + 4 = 12
a = 12 - 4
a = 8
Finding 29th term,
an = a + (n-1)d
a29 = 8 + (29-1)2
= 8 + 28×2
= 8 + 56
= 64
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