If the 4-digit number 2X Y7 is exactly divisible by 3, then which of the following is the least value of (X + Y)?
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Answered by
0
Answer:
0
Step-by-step explanation:
x = 0 and y = 0 then 2007 is the least number divisivle by 3 according to the given question
therefore 0 + 0 = 0
Answered by
0
Answer:
we know that the divisibility rule for 3 is sum of all digits should be divisible by 3
2XY7 is the number
2+X+Y+7=9+(X+Y)
least number for (X+Y) is 0 bcoz 9+0 is 9 which is divisible by 3
so the least value of X+Y is 0
hope it helps u..
thank uhh
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