Question

If the 4th, 7th and 10th terms of a G.P. be a, b, c respectively, then what is the relation between a, b, c?

Answer 1

Step-by-step explanation:

Let first term of G.P. = A and common ratio = r

We know that nth term of G.P. = Arn^−1

Now t4 = a = Ar^3, t7 = b = Ar^6 and t10= c = Ar^9

Relation b2 = ac is true because

B2 = (Ar^6)^2 = A^2r^12 and ac = (Ar^3) * (Ar^9) = A^2r^12

As we know, if xy + 2y² + yz = xy + xz + y² + yz are in A.P., then

2n^2 + 5n − 2n^2 + 4n − 2 − 5n + 5 = 4n + 3 terms of a G.P. are always in G.P.,

Therefore, a, b, c will be in G.P. i.e. 2, 5, 8, 11, 14 = 40.

Hope it helps you friend

Answer 2

Answer:

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Step-by-step explanation:

a is square and b is square