if the 4th , 7th , and 10th terms of a GP are a,b,and c respectively prove that b square = ac
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hence proved. . . ..
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Dear Student,
◆ Answer with Explanation -
Let a be first term and r be common ratio for GP.
t4 = ar^3
t7 = ar^6
t10 = ar^9
Let's take LHS,
LHS = b^2
LHS = (ar^6)^2
LHS = a^2.a^12
LHS = ar^3 × ar^9
LHS = a × c
LHS = RHS
Thus, proved.
Thanks dear. Hope this helps you...
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