if the 4th term of an A.p is 13 & 7th term of the same A.P is 25 what is their 15th term
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Answered by
1
Answer:
Simplification of the above question cane written as
a+ 3d = 13
=>3d = 13 - a. (1)
a+ 9d = 25
=> 9d = 25- a
3(3d) = 25 - a. (2)
Substituting
(1) in (2)
3(13 - a) = 25 - a
39 - 3a = 25 - a
2a. = 14
a = 7
From (1) d= 2
17th term = 7 + 15(2) =37 the answer
Answered by
0
Answer:
The 15th term of the A.P. is 57.
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