If the 5 th and 21 st term of an AP are 14 and -14 respectively than which term of the AP is 0
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Answer:
13nth term of AP = 0
Step-by-step explanation:
5th term of AP = a+4d
21st term of AP= a+20d
given,
a+4d= 14..........(1)
a+20d= -14.......(2). from these eqns.
=> 16d= -28
=> d= -28/16= -7/4
=> a+ 4×-7/4= 14
=> a = 21
let nth term is 0
=> a+(n-1)d =21+(n-1)(-7/4)= 0
=> (n-1)(-7/4) = -21
=> n-1 = -21× -4/7= 12
=> n= 13
thus, 11nth term of AP is 0.
short method:-
adding eqns (1) and (2)
2a+24d=0
=> a+12d = 0 => a+ (13-1)d=0
= 13nth term =0
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