If the 5th term is 8times the 1st term and 8th term exceeds twice the 4th term by 12 then d is
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Answer:
3
Step-by-step explanation:
let the first term be a and the common difference be d
aₙ = a + (n-1)d
a₅ = 8a
a + 4d = 8a
4d = 7a
a ₈ = a ₄ + 12
a + 7d = a + 3d + 12
4d = 12
d = 3
a = 12/7
the value of d is 3
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