If the 5th term of an AP is zero , then 26th term is __ the 12th term.
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Given,
Fifth term of an AP=0……….(i) Let first term of the AP be a
Let Common Difference of the AP be d
We know that,
General Term of an AP is -----
Tn=a+((n-1)*d)
5th term of the AP is -----
Tn=a+((n-1)*d)
T5= a+(5-1)d
0 = a+4d
a = -4d
26th Term of the AP is ----
Tn = a+(n-1)d
T26 = a+(26-1)d
T26 = a+ 25d
12th Term of the AP-----
Tn = a+(n-1)d
T26 = a+(12-1)d
T26 = a+ 11d
Therefore, no of times of 12th term which equals 26th term is --------
T26/T12 = (a+25d)/(a+11d)
= (-4d+25d)/(-4d+11d)
=21d/7d
= 3
If the 5th term of an AP is zero, then 26th term is 3 times the 12th term.
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