Question

If the 6 times of sixth term of an ap is equal to 8 times of its eight term then show that the 14th term of it is zero

Answer 1

Step-by-step explanation:

6a6=8a8

or,6(a+5d)=8(a+7d)

or, 6a+30d=8a+56d

or,2a= -26d

or,a= -13d

we know,

a14= a +13d

putting a= -13, here

a14= -13d+13d=0

HENCE, PROVED