If the 6th term of an ap is -10 and its 10th term is minus 26 then find the 15th term of an ap
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Step-by-step explanation:
t6=-10
a+(6-1)d=-10
a+5d=-10. --- 1
d=(t(m)-t(n))/m-n
=(-26+10)/10-6
=-16/4
=-4
d=-4
by 1
a+5d= -10
a+5(-4)=-10
a=-10+20
a=10
Thus
a+(n-1)=t(n)
t(15)=10+(15-1)(-4)
=10-(14)*4
=10-56
=-46
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