if the 6th term of an AP is -10and its 15th term is -46 then find the 10th term of AP
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tenth term is -26
6th term =-10
a+(n-1)d = -10
a+5d=-10__________(1)
15th term = -46
a+(n-1)d =-46
a+14d = -46 _________(2)
(1) - (2)
5d - 14d = -10- -46
5d - 14d = -10 + 46
-9d = 36
d= 36/-9 = -4
substituting d in (1)
a+5× -4 =-10
a + -20=-10
a= -10+20
a = 10
tenth term = a+9d
= 10+9×-4
= 10 -36
= -26
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