if the 6th term of an ap is 34 and 16 term is 95 then find the AP
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Step-by-step explanation:
6th term= 34
16th term= 94
First make the equation:
a+5d= 34. equation 1
a+15d=94. equation 2
subtract equation 1 from equation 2 we get,
10d= 60
d= 6
put the value of d in equation 1 we get,
a+5×6= 34
a+30=34
a= 4
so the A.P will be
4,10,16,22,28,34....
a is the first number of A.P
d is the difference in every number in A.P
The statement is wrong the 16 term should be 94 in the place of 95.
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