If the 6th term of an ap is zero then show that 33rd term is 3 times its 15 term
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a+5d=0 then 33 term means a+32d =a+5d+27d=27d since a+5d=0,
then 3 times Of 15 term means 3×(a+14d) =3a+42d= 3a+15d+27d =27d=33rd term proved.
then 3 times Of 15 term means 3×(a+14d) =3a+42d= 3a+15d+27d =27d=33rd term proved.
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