Question

If the 7th and 13th term of an arithmetic progression and 34 and 64 respectively . Then the common difference is

Answer 1

Answer:

The common difference is 5

Explanation:

An arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

In general AP is given by,

$a_n=a+(n-1)d$; where a is the initial term , d is the common difference and n is the number of terms.

Given:

$a_7=34$

$a_13=64$

$a_7=a+(7-1)d=a+6d$

$34=a+6d$                   ....(1)

$a_13=a+(13-1)d=a+12d$

$64=a+12d$                ......(2)

Now, solving equation (1) and (2) simultaneously we get, d=5.

Therefore, the common difference is , d=5