If the 7th term of an A. P. is 1/9 and the 9th terms is 1/7,find it's (63)rd term.
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Step-by-step explanation:
term7=1/9. term 9=1/7
a+6d=1/9-(1) a+8d=1/7-(2)
(1)-(2)
a+6d=1/9
a+8d=1/7. 1/9-1/7=7-9/63
=-2/63
- - -
-2d=-2/63
d=2/63.1/2
d=1/63
From (1),a+6d=1/9
a+6.1/63=1/9
a+6/63=1/9
a=1/9-6/63
a=7-6/63
a=1/63
term 63=a+62d
=1/63+62.1/63
=1+62/63
=63/63
=1
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