If the 7th term of an Ap is equal to 11/7 times of 1th term then find 18th term
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Step-by-step explanation:
the 7th term is a+6d
the 1th term is a
according to the question
a+6d=11(a+10d)/7
7a+42d=11a+110d
a = -17d
then 18th term is a+17d
then putting the value of a in upper equation
then -17d+17d=0
the 18th term is 0
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