if the 7th term of an ap is zero prove that its 27th term is five times its 11th term
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T7 = a+6d
T11 = a+10d
T27 = a+26d
a+6d = 0
a = -6d
T27 = -6d+26d = 20d
T11 = -6d+10d = 4d
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