if the 8term of an ap is 37 and 15term is 15 more than the 12 term find the sum of the first 20 term of the ap
Answers
Answer:
The sum of first 20 terms is 990.
Step-by-step explanation:
Given :-
- The 8th term of an AP is 37 and 15th term is 15 more than the 12th term.
To find :-
- Sum of the first 20 terms of the AP.
Solution :-
Formula used :
- a = first term.
- d = common difference.
★ The 8th term of the AP is 37.
Now find the 15th term and 12th term of the AP.
★
★
According to the question ,
→ d = 5
Now put d = 5 in eq(i).
a+7d = 37
→ a + 7×5 = 37
→ a + 35 = 37
→ a = 37-35
→ a = 2
Formula used :
Sum of first 20 terms ,
=20/2[2×2+(20−1)×5]
=10[4+19×5]
=10[4+95]
=10×99
=990
Therefore, the sum of first 20 terms is 990.
Solution :
If the 8th term of an A.P. is 37 & 15th term is 15 more than the 12 term.
We know that formula of an A.P;
- a is the first term.
- d is the common difference.
- n is the term of an A.P.
A/q
→ a8 = 37
→ a + (8-1)d = 37
→ a + 7d = 37
→ a = 37 - 7d...................(1)
&
→ a15 = a12 + 15
→ a + (15-1)d = a + (12-1)d + 15
→ a + 14d = a + 11d + 15
→ 37 - 7d + 14d = 37 - 7d + 11d + 15 [from (1)]
→ 37 + 7d = 37 + 4d + 15
→ 37 + 7d = 52 + 4d
→ 7d - 4d = 52 - 37
→ 3d = 15
→ d = 15/3
→ d = 5
∴ Putting the value of d in equation (1),we get;
→ a = 37 - 7(5)
→ a = 37 - 35
→ a = 2
Now;
As we know that formula of the sum of an A.P;
→ S20 = 20/2 [2(2) + (20-1) (5)
→ S20 = 10 [4 + 19 × 5]
→ S20 = 10 [4 + 95]
→ S20 = 10 × 99
→ S20 = 990
Thus;
The sum of the first 20 term of the A.P. will be 990 .