If the 8th term of an A.P. is 31 and 15th term is 16 more than the 11th term. Find the A.P.
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SOLUTION
Let first term of A.P.= a
common difference= d
Then as per given,
a8= 31 & a15 = 16+ a11
=)a+7d = 31 & a+14d= 16+(a+10d)
=)a+7d= 31 & 4d = 16
=) a+ 7d= 31 & d= 4
=) a+ 7(4)= 31
=) a+ 28= 31
=) a=31-28
=) a= 3
Hence, the required A.P
=) a, a+d, a+2d, a+3d,.....
=)3, 7, 11, 15,.....
Hope it helps ☺️⬆️
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