If the 8th term of an ap is 0 show that the 20th term is thrice the 12th term
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Answered by
8
a8 = 0
=> a + 7d = 0
=> a = -7d
a20 = a + 19d = -7d + 19d = 12d......(1)
a12 = a +11d = -7d +11d = 4d.......(2)
dividing equation (1) by equation (2),
a20/a12 = 12d/4d
=> a20/ a12 = 3
=> a20 = 3 × a12
Hence, proved
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=> a + 7d = 0
=> a = -7d
a20 = a + 19d = -7d + 19d = 12d......(1)
a12 = a +11d = -7d +11d = 4d.......(2)
dividing equation (1) by equation (2),
a20/a12 = 12d/4d
=> a20/ a12 = 3
=> a20 = 3 × a12
Hence, proved
Hope it helps, if it does,
plz mark as BRAINLIEST!!!
Answered by
5
Answer:
Step-by-step explanation:
a8 = 0
=> a + 7d = 0
=> a = -7d
So
a20 = a + 19d = -7d + 19d = 12d......(1)
a12 = a +11d = -7d +11d = 4d.......(2)
dividing equation (1) by equation (2),
We get
a20/a12 = 12d/4d
=> a20/ a12 = 3
=> a20 = 3 × a12
Hence, proved
Hope it helps, if it does,
plz mark as BRAINLIEST!!!
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