If the 8th term of an ap is 37 and the 15th term is 15 more than the 12th term find the sum of 15 th term
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Given:-T8=37
T15=T12+15,
a+14d=a+11d+15
Solving the Equation we get,3d=15 or d=5
a+7(5)=37,hence a=2
Sum of 1st 15 terms is:-n/2(2a+(n-1)d)
15/2(2*2+14*5)=555
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