If the 9th term of an A.P is 0, prove that its 29th term is double the 19th term.
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Answered by
18
a9 = 0
a + 8d = 0
a = -8d ...... (1)
Now, to prove,
a29 = 2a19
a + 28d = 2(a + 18d)
a + 28d = 2a + 36d
-8d + 28d = -16d + 36d
20d = 20d
Since LHS=RHS, hence proved.
a + 8d = 0
a = -8d ...... (1)
Now, to prove,
a29 = 2a19
a + 28d = 2(a + 18d)
a + 28d = 2a + 36d
-8d + 28d = -16d + 36d
20d = 20d
Since LHS=RHS, hence proved.
Answered by
7
Answer:
a9 = 0
a + 8d = 0
a = -8d ...... (1)
Now, to prove,
a29 = 2a19
a + 28d = 2(a + 18d)
a + 28d = 2a + 36d
-8d + 28d = -16d + 36d
20d = 20d
Since LHS=RHS, hence proved.
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