Question

if the 9th term of an AP be zero,then the ratio of its 29th and 19th term is equal to??

Answer 1

thanks for your question and it is your answer

Answer 2

Answer:

• 2:1 is the correct option.........

Step-by-step explanation:

Let the first term, common difference and number of terms of an AP are a, d and n respectively.

Given that, 9th term of an AP, T9 = 0  [∵ nth term of an AP, Tn = a + (n-1)d]

⇒ a + (9-1)d = 0

⇒ a + 8d = 0 ⇒ a = -8d   ...(i)

Now, its 19th term , T19 = a + (19-1)d

= - 8d + 18d [from Eq.(i)]

= 10d ...(ii)

and its 29th term, T29 = a+(29-1)d  

= -8d + 28d [from Eq.(i)]

= 20d = 2 × T19  

Hence, its 29th term is twice its 19th term