if the 9th term of an AP is (2n+1) find the sum of first n terms of the AP
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here is your answer ⤵️
➡️ l = 2n+1
↪️ n=1
↪️ a=2(1)+1
↪️ a=3
➡️ A.P.=n/2(a+l)
➡️ A.P.=n/2(3+2n+1)
➡️ n/2(2n+4)
➡️ n(n+2)
Hence, sum of first n terms of an A.P. is n(n+2)
__hope it help ✌️
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